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6(1+2x^2)=4x(1+3x)
We move all terms to the left:
6(1+2x^2)-(4x(1+3x))=0
We add all the numbers together, and all the variables
6(1+2x^2)-(4x(3x+1))=0
We multiply parentheses
12x^2-(4x(3x+1))+6=0
We calculate terms in parentheses: -(4x(3x+1)), so:We get rid of parentheses
4x(3x+1)
We multiply parentheses
12x^2+4x
Back to the equation:
-(12x^2+4x)
12x^2-12x^2-4x+6=0
We add all the numbers together, and all the variables
-4x+6=0
We move all terms containing x to the left, all other terms to the right
-4x=-6
x=-6/-4
x=1+1/2
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